continuous imprv.
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@ -4,8 +4,8 @@
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# longest substring without repeating characters
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def solution(s: str) -> int:
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if len(s) == 0:
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return 0
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if len(s) <= 1:
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return len(s)
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longest = -1
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@ -21,7 +21,6 @@ def solution(s: str) -> int:
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for t in range(f+1, len(s)):
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cs = count(s[f:t+1])
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longest = cs if cs > longest else longest
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longest = 1 if longest < 1 else longest
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return longest
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